The eccentricity of the ellipse $(x-3)^2 + (y-4)^2 = \frac{y^2}{9} + 16$ is -

  • A
    $\frac{\sqrt{3}}{2}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{3\sqrt{2}}$
  • D
    $\frac{1}{\sqrt{3}}$

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