The effect of the uncertainty principle is significant only for the motion of microscopic particles and is negligible for macroscopic particles. Justify the statement with the help of a suitable example.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The Heisenberg uncertainty principle is given by $\Delta x \cdot \Delta v \geq \frac{h}{4 \pi m}$.
For a microscopic particle like an electron $(m = 9.11 \times 10^{-31} \ kg)$,the uncertainty is significant.
For a macroscopic object of mass $1 \ mg$ $(10^{-6} \ kg)$:
$\Delta x \cdot \Delta v = \frac{h}{4 \pi m} = \frac{6.626 \times 10^{-34} \ J \ s}{4 \times 3.1416 \times 10^{-6} \ kg} \approx 0.527 \times 10^{-28} \ m^2 \ s^{-1}$.
This value is extremely small and physically insignificant,which is why the uncertainty principle is negligible for macroscopic objects.

Explore More

Similar Questions

The equation $\Delta x \cdot \Delta p \geqslant \frac{h}{4\pi}$ represents:

The possibility of finding an electron in an orbital was conceived by

An electron is moving with a velocity of $600 \, m/s$ with an accuracy of $0.005\%$. The uncertainty in its position will be: ($h = 6.6 \times 10^{-34} \, kg \, m^2 \, s^{-1}$,mass of electron $m_e = 9.1 \times 10^{-31} \, kg$)

An electron moves with a speed of $300 \ ms^{-1}$ with an uncertainty of $0.01\%$. Find the uncertainty in its position.

The uncertainty in the velocities of two particles $A$ and $B$ are $0.03 \ m \ s^{-1}$ and $0.01 \ m \ s^{-1}$ respectively. The mass of $B$ is four times the mass of $A$. The ratio of uncertainties in their positions is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo