The efficiency of a Carnot heat engine:

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(B) The efficiency of a Carnot heat engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source (hot rese

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is independent of the working substance

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(B) The efficiency of a Carnot heat engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source (hot reservoir) and $T_2$ is the temperature of the sink (cold reservoir).From this expression,it is clear that the efficiency depends solely on the temperatures of the source and the sink.It is independent of the nature of the working substance used in the engine.Therefore,option $B$ is the correct statement.

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