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(B) The given electric field is of the form $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the standard wave equation, the wave is moving in the

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moving along $X$-direction with frequency $10^6 \, 	ext{Hz}$ and wavelength $200 \, 	ext{m}$

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(B) The given electric field is of the form $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the standard wave equation, the wave is moving in the positive $X$-direction.From the equation, the angular frequency is $\omega = 2\pi 	imes 10^6 \, 	ext{rad/s}$.Since $\omega = 2\pi f$, we have $2\pi f = 2\pi 	imes 10^6 \, 	ext{Hz}$, which gives $f = 10^6 \, 	ext{Hz}$.The wave number is $k = \pi 	imes 10^{-2} \, 	ext{rad/m}$.Since $k = \frac{2\pi}{\lambda}$, we have $\frac{2\pi}{\lambda} = \pi 	imes 10^{-2}$.Solving for wavelength, $\lambda = \frac{2\pi}{\pi 	imes 10^{-2}} = 2 	imes 10^2 = 200 \, 	ext{m}$.Thus, the wave is moving along the $X$-direction with a frequency of $10^6 \, 	ext{Hz}$ and a wavelength of $200 \, 	ext{m}$.

The electric field part of an electromagnetic wave in a medium is represented by:
$E_x = 0;$
$E_y = 2.5 \, \text{N/C} \cos \left[ \left( 2\pi \times 10^6 \, \text{rad/s} \right) t - \left( \pi \times 10^{-2} \, \text{rad/m} \right) x \right];$
$E_z = 0.$
The wave is:

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The electric field part of an electromagnetic wave in a medium is represented by:$E_x = 0;$$E_y = 2.5 \, \text{N/C} \cos \left[ \left( 2\pi \times 10^6 \, \text{rad/s} \right) t - \left( \pi \times 10^{-2} \, \text{rad/m} \right) x \right];$$E_z = 0.$The wave is: