The electronic configuration of a metal ion in its complex is $[Ar] 3d^4$. For this metal complex,$\Delta_o < P$ ($P=$ energy required for electron pairing in a single orbital). The distribution of electrons in the complex is:

Given below are two statements: Statement $I$: Each electron in $e_g$ orbitals destabilizes the orbitals by $+0.6\Delta_o$ and each electron in the $t_{2g}$ orbitals stabilizes the orbitals by $-0.4\Delta_o$ in an octahedral field on the basis of crystal field theory. Statement $II$: All the $d$-orbitals of the transition metals have the same energy in their free atomic state but when a complex is formed the ligands destroy the degeneracy of these orbitals on the basis of crystal field theory. In the light of the above statements, choose the correct answer from the options given below:

Two complexes $[Cr(H_2O)_6]Cl_3 \ (A)$ and $[Cr(NH_3)_6]Cl_3 \ (B)$ are violet and yellow coloured respectively. The incorrect statement regarding them is

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

If $\Delta_{0} < P$,then what is the electronic arrangement of the metal atom/ion in a complex with $d^4$ configuration?

$A$ transition metal $(M)$ among $Mn, Cr, Co$ and $Fe$ has the highest standard electrode potential $(M^{3+} / M^{2+})$. It forms a metal complex of the type $[M(CN)_6]^{4-}$. The number of electrons present in the $e_g$ orbital of the complex is $.........$