Easy
The electronic configuration of cobalt ($Co$,atomic number $27$) is:
- A$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^1, 4s^2$
- B$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^7, 4s^2$
- C$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^3, 4s^2$
- D$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^5, 4s^2$
Explore More
Similar Questions
In an atom,the total number of electrons having quantum numbers $n=4$,$|m_{\ell}|=1$ and $m_s=-1/2$ is
How many electrons in an atom can have the following quantum numbers?
$(a)$ $n = 4, m_s = -\frac{1}{2}$
$(b)$ $n = 3, l = 0$
$(a)$ $n = 4, m_s = -\frac{1}{2}$
$(b)$ $n = 3, l = 0$
Easy
View SolutionAn atom of an element contains $29$ electrons and $35$ neutrons. Deduce
$(i)$ the number of protons and
$(ii)$ the electronic configuration of the element.
$(i)$ the number of protons and
$(ii)$ the electronic configuration of the element.
Medium
View SolutionWhich electronic arrangement shows the ground state of an element?
Easy
View SolutionThe correct order of energy for orbitals in a multi-electron atom is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo