The electronic configurations of four elements $L$,$P$,$Q$,and $R$ are given as: $L (1s^2, 2s^2 2p^4)$; $Q (1s^2, 2s^2 2p^6, 3s^2 3p^5)$; $P (1s^2, 2s^2 2p^6, 3s^1)$; $R (1s^2, 2s^2 2p^6, 3s^2)$. The formulas of the ionic compounds that can be formed between these elements are:

  • A
    $L_2P, RL, PQ$ and $R_2Q$
  • B
    $LP, RL, PQ$ and $RQ$
  • C
    $P_2L, RL, PQ$ and $RQ_2$
  • D
    $LP, R_2L, P_2Q$ and $RQ$

Explore More

Similar Questions

Find out the correct order of ionic character in the following molecules:
$(i)$ $O_2$
$(ii)$ $K_2O$
$(iii)$ $N_2$
$(iv)$ $LiF$

Amongst sodium halides $(NaF, NaCl, NaBr, NaI)$,$NaF$ has the highest melting point because of:

Difficult
View Solution

As compared to covalent compounds,electrovalent compounds generally have:

The lattice energies of $NaCl$,$NaF$,$KCl$,and $RbCl$ follow the order:

Magnesium reacts with an element $(X)$ to form an ionic compound. If the ground state electronic configuration of $(X)$ is $1s^{2} 2s^{2} 2p^{3},$ the simplest formula for this compound is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo