(C) The elevation in boiling point is given by the formula: $\Delta T_{b} = i \times K_{b} \times m$. Given: $\Delta T_{b} = 0.01 \ K$,$i = 1.92$,$K_{

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The elevation in boiling point is given by the formula: $\Delta T_{b} = i \times K_{b} \times m$. Given: $\Delta T_{b} = 0.01 \ K$,$i = 1.92$,$K_{b} = 0.52 \ K \ kg \ mol^{-1}$. Rearranging the formula for molality $(m)$: $m = \frac{\Delta T_{b}}{i \times K_{b}}$. Substituting the values: $m = \frac{0.01}{1.92 \times 0.52} = \frac{0.01}{0.9984} \approx 0.010 \ m$.

Class 12 Chemistry Solutions Colligative properties of electrolyte

Medium

The elevation in the boiling point of an aqueous solution of $NaCl$ is $0.01^{\circ}C$. If its van't Hoff factor is $1.92$,the molality of the $NaCl$ solution is: $(K_{b} \text{ for water} = 0.52 \ K \ kg \ mol^{-1})$ (in $m$)

AP EAMCET 2019 All AP EAMCET

A
$0.01$
B
$0.001$
C
$0.010$
D
$0.02$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solutions

Subtopic

Colligative properties of electrolyte

Previous Year

AP EAMCET 2019 Paper All AP EAMCET years →

$2.0 \, m \, CH_3COOH$ undergoes $100 \%$ dimerization in benzene. It will be isotonic with which of the following?

Medium

View Solution

Which of the following $0.10 \ m$ aqueous solution will have the lowest freezing point?

MediumAIPMT 1997

View Solution

When $10^{-3} \ M$ solution of glucose in water freezes at $-0.0186^{\circ} C$,then at what temperature $10^{-3} \ M$ solution of $NaCl$ will freeze (in $^{\circ} C$)?

EasyAP EAMCET 2023

View Solution

Which one has the highest boiling point?

EasyAIPMT 1990

View Solution

$A^{2+}$,$B^{2+}$ and $C^{-}$ form an ionic complex like $A_{x-2}[B(C)_x]_2$. If the complex is $75 \%$ dissociated in a solvent with $i=4$,the coordination number of $B$ is:

DifficultTS EAMCET 2020

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The elevation in the boiling point of an aqueous solution of $NaCl$ is $0.01^{\circ}C$. If its van't Hoff factor is $1.92$,the molality of the $NaCl$ solution is: $(K_{b} \text{ for water} = 0.52 \ K \ kg \ mol^{-1})$ (in $m$)

Similar Questions

$2.0 \, m \, CH_3COOH$ undergoes $100 \%$ dimerization in benzene. It will be isotonic with which of the following?

Which of the following $0.10 \ m$ aqueous solution will have the lowest freezing point?

When $10^{-3} \ M$ solution of glucose in water freezes at $-0.0186^{\circ} C$,then at what temperature $10^{-3} \ M$ solution of $NaCl$ will freeze (in $^{\circ} C$)?

Which one has the highest boiling point?

$A^{2+}$,$B^{2+}$ and $C^{-}$ form an ionic complex like $A_{x-2}[B(C)_x]_2$. If the complex is $75 \%$ dissociated in a solvent with $i=4$,the coordination number of $B$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module