The energy dissipated by a resistor is 10 , m | vedclass

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(D) The formula for energy dissipated by a resistor is given by $H = i^{2}Rt$.Given:Energy $H = 10 \, mJ = 10 	imes 10^{-3} \, J$Time $t = 1 \, s$Cur

Vedclass · Accepted Answer

$2500$

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(D) The formula for energy dissipated by a resistor is given by $H = i^{2}Rt$.Given:Energy $H = 10 \, mJ = 10 	imes 10^{-3} \, J$Time $t = 1 \, s$Current $i = 2 \, mA = 2 	imes 10^{-3} \, A$Rearranging the formula to solve for resistance $R$:$R = \frac{H}{i^{2}t}$Substituting the values:$R = \frac{10 	imes 10^{-3}}{(2 	imes 10^{-3})^{2} 	imes 1}$$R = \frac{10 	imes 10^{-3}}{4 	imes 10^{-6} 	imes 1}$$R = \frac{10 	imes 10^{3}}{4} = 2.5 	imes 10^{3} = 2500 \, \Omega$.

The energy dissipated by a resistor is $10 \, mJ$ in $1 \, s$ when an electric current of $2 \, mA$ flows through it. The resistance is $....... \, \Omega$ (Round off to the Nearest Integer).

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