The energy equivalent of $0.5\, g$ of a substance is $........\, J$.

The binding energy $(BE)$ per nucleon for an element is $7.14 \text{ MeV}$. If the total $BE$ of the element is $28.6 \text{ MeV}$, then the number of nucleons in the element is:

From the given data,the amount of energy required to break the nucleus of aluminium ${ }_{13}^{27} {Al}$ is $x \times 10^{-3} {J}$.
Mass of neutron $= 1.00866 \, {u}$
Mass of proton $= 1.00726 \, {u}$
Mass of aluminium nucleus $= 26.98154 \, {u}$
(Assume $1 \, {u}$ corresponds to $1 \, {J}$ of energy for the purpose of this calculation)
(Round off to the nearest integer)

Degenerate electron pressure will not be sufficient to prevent the core collapse of a white dwarf if its mass becomes $n$ times the solar mass. The value of $n$ is:

The binding energy per nucleon of a nucleus ${}_Z X^A$ at rest is $6 \ MeV$. It undergoes $\beta^-$ decay as shown below:
${}_Z X^A \to {}_{Z+1} Y^A + {}_{-1}^0 e + \bar{\nu}$
The total kinetic energy $(K.E.)$ of the products is $3 \ MeV$. The binding energy per nucleon of $Y$ (in $MeV$) is:

What is the binding energy of ${ }_{14}^{29} Si$ whose atomic mass is $28.976495 u$ (in $MeV$)?
Mass of proton $= 1.007276 u$
Mass of neutron $= 1.008664 u$
(Neglect the electron mass) (Assume $1 u = 931.5 MeV$)