(C) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.Since the battery remains connected,the potential difference $V$ across the p

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(C) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.Since the battery remains connected,the potential difference $V$ across the plates remains constant.The capacitance of a parallel plate capacitor is $C = \frac{A \epsilon_0}{d}$,which implies $C \propto \frac{1}{d}$.If the distance $d$ is doubled $(d' = 2d)$,the new capacitance $C'$ becomes $C' = \frac{C}{2}$.The new energy $E'$ is given by $E' = \frac{1}{2} C' V^2$.Substituting $C' = \frac{C}{2}$,we get $E' = \frac{1}{2} (\frac{C}{2}) V^2 = \frac{1}{2} (\frac{1}{2} C V^2) = \frac{E}{2}$.

Class 12 Physics Electrostatic Potential and Capacitance Energy Stored in a Capacitor

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The energy of a parallel plate capacitor when connected to a battery is $E$. With the battery still in connection,if the plates of the capacitor are separated so that the distance between them is twice the original distance,then the electrostatic energy becomes

AP EAMCET 2015 All AP EAMCET

A
$2\ E$
B
$\frac{E}{4}$
C
$\frac{E}{2}$
D
$4\ E$

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Electrostatic Potential and Capacitance

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Energy Stored in a Capacitor

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The energy of a parallel plate capacitor when connected to a battery is $E$. With the battery still in connection,if the plates of the capacitor are separated so that the distance between them is twice the original distance,then the electrostatic energy becomes

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