The equation $2y^2 - xy - x^2 + 6x - 8 = 0$ represents

  • A
    $A$ pair of straight lines
  • B
    $A$ circle
  • C
    An ellipse
  • D
    $A$ parabola

Explore More

Similar Questions

The equation $x^2 + ky^2 + 4xy = 0$ represents two coincident lines,if $k =$

$A$ pair of straight lines drawn through the origin forms an isosceles triangle right-angled at the origin with the line $2x + 3y = 6$. The area (in sq. units) of the triangle so formed is

If the slope of one of the two lines represented by $\frac{x^2}{a} + \frac{2xy}{h} + \frac{y^2}{b} = 0$ is twice that of the other,then $ab : h^2 = $

If the angles made by the lines represented by the equation $ax^2 + 2hxy + by^2 = 0$ with the $X$-axis are $\alpha$ and $\beta$, then $\tan(\alpha + \beta)$ is

If one of the lines given by $k x^2 + x y - y^2 = 0$ bisects the angle between the coordinate axes,then the values of $k$ are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo