The equation x^2 - 7xy + 12y^2 = 0 represents | vedclass

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(D) The given equation is $x^2 - 7xy + 12y^2 = 0$. Factorizing the quadratic expression: $x^2 - 3xy - 4xy + 12y^2 = 0$. $x(x - 3y) - 4y(x - 3y) = 0$.

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Pair of non-perpendicular intersecting straight lines

Vedclass · Answer

(D) The given equation is $x^2 - 7xy + 12y^2 = 0$. Factorizing the quadratic expression: $x^2 - 3xy - 4xy + 12y^2 = 0$. $x(x - 3y) - 4y(x - 3y) = 0$. $(x - 3y)(x - 4y) = 0$. This represents two straight lines $x - 3y = 0$ and $x - 4y = 0$ passing through the origin. Since the slopes are $m_1 = 1/3$ and $m_2 = 1/4$,and $m_1 	imes m_2 
eq -1$,the lines are non-perpendicular and intersect at the origin. Therefore,the correct option is $D$.

The equation $x^2 - 7xy + 12y^2 = 0$ represents

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