The equation of a simple harmonic wave produced in a string under a tension of $0.4 \,N$ is given by $y=4 \sin (3x+60t) \,m$. The mass per unit length of the string is:

The equation of a wave on a string of linear mass density $0.02 \text{ kg m}^{-1}$ is $Y = 0.01 \sin [2\pi (t/0.02 - x/0.50)] \text{ m}$. The tension in the string is (in $\text{ N}$)

$A$ transverse wave is travelling on a string with velocity $V$. The extension in the string is $x$. If the string is extended by $50 \%$,the speed of the wave along the string will be nearly (Hooke's law is obeyed).

$A$ composite string is made up by joining two strings of different mass per unit length,$\mu$ and $4\mu$. The composite string is under the same tension $T$. $A$ transverse wave pulse,$Y = (6 \text{ mm}) \sin(5t + 40x)$,where $t$ is in seconds and $x$ is in meters,is sent along the lighter string towards the joint. The joint is at $x = 0$. The equation of the wave pulse reflected from the joint is:

$A$ steel wire has a length of $12 \ m$ and a mass of $2.10 \ kg$. What will be the speed of a transverse wave on this wire when a tension of $2.06 \times 10^4 \ N$ is applied (in $m/s$)?

Two strings with circular cross section and made of same material are stretched to have the same amount of tension. $A$ transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section $R$ is $v_1$,and that in the other string having radius of cross section $R/2$ is $v_2$. Then $\frac{v_2}{v_1} = $