The equation of a travelling wave is y = 60 c | vedclass

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(C) The maximum particle velocity is given by $v_{\max} = \omega A$,where $\omega$ is the angular frequency and $A$ is the amplitude.The wave propagat

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$3.6 	imes 10^{-4}$

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(C) The maximum particle velocity is given by $v_{\max} = \omega A$,where $\omega$ is the angular frequency and $A$ is the amplitude.The wave propagation velocity is given by $v = \frac{\omega}{k}$,where $k$ is the wave number.The ratio of maximum particle velocity to wave velocity is $\frac{v_{\max}}{v} = \frac{\omega A}{\omega / k} = kA$.From the given wave equation $y = 60 \cos (1800t - 6x)$,we identify:Amplitude $A = 60 	ext{ microns} = 60 	imes 10^{-6} 	ext{ m}$.Wave number $k = 6 	ext{ m}^{-1}$.Therefore,the ratio is $\frac{v_{\max}}{v} = kA = 6 	imes (60 	imes 10^{-6}) = 360 	imes 10^{-6} = 3.6 	imes 10^{-4}$.

The equation of a travelling wave is $y = 60 \cos (1800t - 6x)$,where $y$ is in microns,$t$ is in seconds,and $x$ is in metres. The ratio of maximum particle velocity to the velocity of wave propagation is:

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