The equation of a wave on a string of linear mass density $0.04 \ kg \ m^{-1}$ is given by $y = 0.02 \sin \left[ 2\pi \left( \frac{t}{0.04 \ s} - \frac{x}{0.50 \ m} \right) \right] \ m$. The tension in the string is .... $N$.

$A$ uniform metal wire of length $L$,mass $M$,and density $\rho$ is under a tension $T$. If the speed of a transverse wave along the wire is $V$,then the area of cross-section of the wire is:

One end of a string is tied to the ceiling of a lift and a load is attached at the bottom end of the string. When the lift is moving upwards with an acceleration of $2.1 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is $88 \,ms^{-1}$. If the lift moves downwards with an acceleration of $1.9 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is (take $g=10 \,ms^{-2}$): (in $\,ms^{-1}$)

The given graph illustrates a transverse wave travelling on a string at a particular instant,and the points $P, Q, R$ and $S$ represent elements of the string. Which of the following statements about the motion of the elements is correct?

$A$ string of mass $M$ and length $L$ hangs freely from a fixed point. The velocity of a transverse wave along the string at a distance $x$ from the free end will be:

$A$ wire of length $50 \ cm$ and weighing $10 \ g$ is attached to a spring at one end and to a fixed wall at the other end. The spring has a spring constant of $50 \ N/m$ and is stretched by $1 \ cm$. If a wave pulse is produced on the string near the wall, then how much time will it take to reach the spring (in $s$)?