(A) Given the equation of state: $\left( P + \frac{aT^2}{V} \right) V^c = (RT + b)$.Divide both sides by $V^c$:$P + \frac{aT^2}{V} = (RT + b) V^{-c}$.

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Given the equation of state: $\left( P + \frac{aT^2}{V} \right) V^c = (RT + b)$.Divide both sides by $V^c$:$P + \frac{aT^2}{V} = (RT + b) V^{-c}$.Isolate $P$:$P = (RT + b) V^{-c} - aT^2 V^{-1}$.Comparing this with the given form $P = AV^m - BV^n$,where $A = (RT + b)$ and $B = aT^2$ (both depend only on temperature):$P = (RT + b) V^{-c} - (aT^2) V^{-1}$.By comparing the exponents of $V$:$m = -c$ and $n = -1$.

Class 11 Physics Units and Measurements Mix Examples-Units, Dimensions and Measurement

Difficult

The equation of state of a gas is given by $\left( P + \frac{aT^2}{V} \right) V^c = (RT + b)$,where $a, b, c$ and $R$ are constants. The isotherms can be represented by $P = AV^m - BV^n$,where $A$ and $B$ depend only on temperature. Then:

A
$m = -c$ and $n = -1$
B
$m = c$ and $n = 1$
C
$m = -c$ and $n = 1$
D
$m = c$ and $n = -1$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Units and Measurements

Subtopic

Mix Examples-Units, Dimensions and Measurement

Match List-$I$ and List-$II$:

List-$I$ List-$II$

$A$. Young's Modulus $(Y)$ $I$. $[M L^{-1} T^{-1}]$

$B$. Co-efficient of Viscosity $(\eta)$ $II$. $[M L^2 T^{-1}]$

$C$. Planck's Constant $(h)$ $III$. $[M L^{-1} T^{-2}]$

$D$. Work Function $(\varphi)$ $IV$. $[M L^2 T^{-2}]$

Choose the correct answer from the options given below:

List-$I$	List-$II$
$A$. Young's Modulus $(Y)$	$I$. $[M L^{-1} T^{-1}]$
$B$. Co-efficient of Viscosity $(\eta)$	$II$. $[M L^2 T^{-1}]$
$C$. Planck's Constant $(h)$	$III$. $[M L^{-1} T^{-2}]$
$D$. Work Function $(\varphi)$	$IV$. $[M L^2 T^{-2}]$