Match List-I and List-II: List-I List | vedclass

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(D) $1$. Young's Modulus $(Y) = \frac{	ext{Stress}}{	ext{Strain}} = \frac{F/A}{\Delta L/L} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$. Thus,$A-II

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$A-III, B-I, C-II, D-IV$

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(D) $1$. Young's Modulus $(Y) = \frac{	ext{Stress}}{	ext{Strain}} = \frac{F/A}{\Delta L/L} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$. Thus,$A-III$.$2$. Co-efficient of Viscosity $(\eta)$: From Stokes' Law,$F = 6\pi\eta rv$,so $\eta = \frac{F}{6\pi rv} = \frac{[MLT^{-2}]}{[L][LT^{-1}]} = [ML^{-1}T^{-1}]$. Thus,$B-I$.$3$. Planck's Constant $(h)$: From $E = hf$,$h = \frac{E}{f} = \frac{[ML^2T^{-2}]}{[T^{-1}]} = [ML^2T^{-1}]$. Thus,$C-II$.$4$. Work Function $(\varphi)$: It is a form of energy,so $[\varphi] = [ML^2T^{-2}]$. Thus,$D-IV$.Therefore,the correct matching is $A-III, B-I, C-II, D-IV$.

List-$I$	List-$II$
$A$. Young's Modulus $(Y)$	$I$. $[M L^{-1} T^{-1}]$
$B$. Co-efficient of Viscosity $(\eta)$	$II$. $[M L^2 T^{-1}]$
$C$. Planck's Constant $(h)$	$III$. $[M L^{-1} T^{-2}]$
$D$. Work Function $(\varphi)$	$IV$. $[M L^2 T^{-2}]$

List-$I$	List-$II$
$(A)$ Torque	$(I)$ $Nms^{-1}$
$(B)$ Stress	$(II)$ $Jkg^{-1}$
$(C)$ Latent Heat	$(III)$ $Nm$
$(D)$ Power	$(IV)$ $Nm^{-2}$

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Match List-$I$ with List-$II$.

List-$I$ List-$II$

$(A)$ Torque $(I)$ $Nms^{-1}$

$(B)$ Stress $(II)$ $Jkg^{-1}$

$(C)$ Latent Heat $(III)$ $Nm$

$(D)$ Power $(IV)$ $Nm^{-2}$

Choose the correct answer from the options below.

Although the units of torque and work are the same,why are they not the same physical quantities?

The dimensions of pressure are equal to

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