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(B) Given lines are:$2x + 3y - 1 = 0$  $(i)$$3x + 4y - 6 = 0$  $(ii)$Multiplying $(i)$ by $3$ and $(ii)$ by $2$:$6x + 9y - 3 = 0$$6x + 8y - 12 = 0$Sub

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$2x + 5y + 17 = 0$

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(B) Given lines are:$2x + 3y - 1 = 0$  $(i)$$3x + 4y - 6 = 0$  $(ii)$Multiplying $(i)$ by $3$ and $(ii)$ by $2$:$6x + 9y - 3 = 0$$6x + 8y - 12 = 0$Subtracting the equations: $y + 9 = 0 \Rightarrow y = -9$.Substituting $y = -9$ in $(i)$: $2x + 3(-9) - 1 = 0$ $\Rightarrow 2x - 27 - 1 = 0$ $\Rightarrow 2x = 28$ $\Rightarrow x = 14$.The point of intersection is $(14, -9)$.The line perpendicular to $5x - 2y = 7$ is of the form $2x + 5y + k = 0$.Since it passes through $(14, -9)$:$2(14) + 5(-9) + k = 0$$28 - 45 + k = 0$$-17 + k = 0 \Rightarrow k = 17$.Thus,the equation is $2x + 5y + 17 = 0$.

The equation of the straight line which is perpendicular to the line $5x - 2y = 7$ and passing through the point of intersection of the lines $2x + 3y - 1 = 0$ and $3x + 4y - 6 = 0$ is

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