The expression left( frac{1}{sqrt{2}}hat{i} + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the given vector be $\vec{P} = \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j}$.The magnitude of a vector $\vec{A} = x\hat{i} + y\hat{j}

Vedclass · Accepted Answer

Unit vector

Vedclass · Answer

(A) Let the given vector be $\vec{P} = \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j}$.The magnitude of a vector $\vec{A} = x\hat{i} + y\hat{j}$ is given by $|\vec{A}| = \sqrt{x^2 + y^2}$.Substituting the values,we get $|\vec{P}| = \sqrt{\left( \frac{1}{\sqrt{2}} \right)^2 + \left( \frac{1}{\sqrt{2}} \right)^2}$.$|\vec{P}| = \sqrt{\frac{1}{2} + \frac{1}{2}} = \sqrt{1} = 1$.Since the magnitude of the vector is $1$,it is a unit vector.

The expression $\left( \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j} \right)$ is a

Similar Questions

Which of the following quantity/quantities are dependent on the choice of orientation of the co-ordinate axes?
$(a)$ $\vec{a}+\vec{b}$
$(b)$ $3a_x+2b_y$
$(c)$ $(\vec{a}+\vec{b}-\vec{c})$

What is the minimum number of coplanar vectors of different magnitudes whose sum can be zero?

Distinguish between a vector quantity and a scalar quantity.

Two vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ lie in a plane,and another vector $\overrightarrow{C}$ lies outside this plane. Then,the resultant of these three vectors,i.e.,$\overrightarrow{A} + \overrightarrow{B} + \overrightarrow{C}$:

The component of a vector $P=3 \hat{i}+4 \hat{j}$ along the direction $(\hat{i}+2 \hat{j})$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module