The factor which is not affecting the conductivity of any solution is

Calculate the concentration of silver nitrate solution if molar conductivity and conductivity of silver nitrate at $25^{\circ} \text{C}$ are respectively $120 \text{ } \Omega^{-1} \text{cm}^2 \text{mol}^{-1}$ and $0.0024 \text{ } \Omega^{-1} \text{cm}^{-1}$. (in $\text{ M}$)

The number of correct statements from the following is $...........$.
$(A)$ Conductivity always decreases with decrease in concentration for both strong and weak electrolytes.
$(B)$ The number of ions per unit volume that carry current in a solution increases on dilution.
$(C)$ Molar conductivity increases with decrease in concentration.
$(D)$ The variation in molar conductivity is different for strong and weak electrolytes.
$(E)$ For weak electrolytes,the change in molar conductivity with dilution is due to decrease in degree of dissociation.

The distance between electrodes of a conductivity cell is $0.98 \ cm$ and area of cross section is $1.96 \ cm^{2}$. What is the cell constant (in $cm^{-1}$)?

The molar conductivity of a $0.04 \text{ M}$ $AB_2$ type salt solution at $300 \text{ K}$ is $200 \text{ } \Omega^{-1} \text{ cm}^2 \text{ mol}^{-1}$. Find the conductivity.

The dissociation constant of acetic acid is $1.75 \times 10^{-5}$ and $\Lambda _{CH_3COOH}^o = 370.6 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acetic acid solution will be: