The false statement in the following is
- A$p \wedge (\sim p)$ is a contradiction
- B$(p$ $\Rightarrow q) \Leftrightarrow (\sim q$ $\Rightarrow \;\sim p)$ is a contradiction
- C$\sim (\sim p) \Leftrightarrow p$ is a tautology
- D$p \vee (\sim p)$ is a tautology
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Similar Questions
Negation of $p \wedge (q \wedge \sim(p \wedge q))$ is
Statement-$1$: $\sim (p \Leftrightarrow \sim q)$ is equivalent to $p \Leftrightarrow q$.
Statement-$2$: $\sim (p \Leftrightarrow \sim q)$ is a tautology.
Statement-$2$: $\sim (p \Leftrightarrow \sim q)$ is a tautology.
Medium
View Solution$p$ and $q$ are two logical statements. If $r: p \rightarrow (\sim p \vee q)$ has truth value false,then the truth values of $p$ and $q$ are respectively:
Identify the type of "Or" used in the following statement and check whether the statement is true or false:
"$A$ rectangle is a quadrilateral or a $5$-sided polygon."
"$A$ rectangle is a quadrilateral or a $5$-sided polygon."
Easy
View SolutionWhich of the following is not a statement?
Easy
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