The first and second ionisation enthalpies of | vedclass

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(A) The $IE$ values indicate that the metal belongs to the $I^{st}$ group because the second $IE$ is very high,suggesting the presence of only one val

Vedclass · Accepted Answer

$1$ and $0.5$

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(A) The $IE$ values indicate that the metal belongs to the $I^{st}$ group because the second $IE$ is very high,suggesting the presence of only one valence electron.Therefore,the metal hydroxide will be of the type $MOH$.The reaction with $HCl$ is:$MOH + HCl \rightarrow MCl + H_{2}O$From the stoichiometry,$1 \; mol$ of $MOH$ reacts with $1 \; mol$ of $HCl$.The reaction with $H_{2}SO_{4}$ is:$2MOH + H_{2}SO_{4} \rightarrow M_{2}SO_{4} + 2H_{2}O$Dividing by $2$ to match $1 \; mol$ of $MOH$:$MOH + \frac{1}{2} H_{2}SO_{4} \rightarrow \frac{1}{2} M_{2}SO_{4} + H_{2}O$From the stoichiometry,$1 \; mol$ of $MOH$ reacts with $0.5 \; mol$ of $H_{2}SO_{4}$.Thus,$1$ mole of $HCl$ and $0.5$ mole of $H_{2}SO_{4}$ are required.

Element	Ionization energy $1^{st}$ $(kJ/mol)$	Ionization energy $2^{nd}$ $(kJ/mol)$
$X$	$495$	$4563$
$Y$	$731$	$1450$

Element	$IE_1$	$IE_2$	$IE_3$	Code	Element
$1$	$2080$	$3963$	$6130$	$(a)$	$H$
$2$	$520$	$7297$	$11810$	$(b)$	$Li$
$3$	$900$	$1758$	$14810$	$(c)$	$Be$
$4$	$800$	$2428$	$3660$	$(d)$	$B$
-	-	-	-	$(e)$	$Ne$

The first and second ionisation enthalpies of a metal are $496$ and $4560 \; kJ \; mol^{-1},$ respectively. How many moles of $HCl$ and $H_{2}SO_{4}$ respectively,will be needed to react completely with $1$ mole of the metal hydroxide?

Similar Questions

Identify the elements $X$ and $Y$ using the ionisation energy values given below :

Element Ionization energy $1^{st}$ $(kJ/mol)$ Ionization energy $2^{nd}$ $(kJ/mol)$

$X$ $495$ $4563$

$Y$ $731$ $1450$

The correct order of second $I.E.$ of $C$,$N$,$O$,and $F$ is:

The correct order of the first ionization enthalpies of the following elements is:

The order of ionisation potential between $He^{+}$ ion and $H$ atom (both species are in gaseous state) is

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