The first excited state of a hydrogen atom is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the kinetic theory of gases,the average kinetic energy of a gas molecule at temperature $T$ is given by $E = \frac{3}{2} kT$,where $k

Vedclass · Accepted Answer

$7.9 	imes 10^4 \, K$

Vedclass · Answer

(A) According to the kinetic theory of gases,the average kinetic energy of a gas molecule at temperature $T$ is given by $E = \frac{3}{2} kT$,where $k$ is the Boltzmann constant $(k = 1.38 	imes 10^{-23} \, J/K)$.To excite a hydrogen atom to the first excited state,the kinetic energy of the colliding particles must be at least $10.2 \, eV$.Converting the energy to Joules: $E = 10.2 	imes 1.6 	imes 10^{-19} \, J = 1.632 	imes 10^{-18} \, J$.Equating the energy: $1.632 	imes 10^{-18} = \frac{3}{2} 	imes (1.38 	imes 10^{-23}) 	imes T$.Solving for $T$: $T = \frac{1.632 	imes 10^{-18} 	imes 2}{3 	imes 1.38 	imes 10^{-23}} \approx 7.88 	imes 10^4 \, K$.Rounding to the nearest given option,$T \approx 7.9 	imes 10^4 \, K$.

The first excited state of a hydrogen atom is $10.2 \, eV$ above its ground state. The temperature needed to excite hydrogen atoms to the first excited level is

Similar Questions

The figure shows the energy levels $P, Q, R, S$ and $G$ of an atom,where $G$ is the ground state. $A$ red line in the emission spectrum of the atom is obtained by an energy level transition from $Q$ to $S$. $A$ blue line can be obtained by which of the following energy level transitions?

In a hydrogen atom,when an electron jumps from the ground state to an excited state,the electron's ...

In the hydrogen atom spectrum, let $E_1$ and $E_2$ be the energies for the transitions $n=2 \rightarrow n=1$ and $n=3 \rightarrow n=2$ respectively. The ratio $E_2 / E_1$ is

What is the excited state of an atom?

Vedclass Test Series

Exam Paper Generator

Online Exam Module