The first term of a harmonic progression is 1 | vedclass

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(B) In a harmonic progression $(H.P.)$,the reciprocals of the terms form an arithmetic progression $(A.P.)$.Given the first term $a_1 = 1/7$ and the s

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$1/29$

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(B) In a harmonic progression $(H.P.)$,the reciprocals of the terms form an arithmetic progression $(A.P.)$.Given the first term $a_1 = 1/7$ and the second term $a_2 = 1/9$,the corresponding terms of the $A.P.$ are $7$ and $9$.The first term of the $A.P.$ is $A = 7$ and the common difference is $d = 9 - 7 = 2$.The $n^{th}$ term of an $A.P.$ is given by $A_n = A + (n - 1)d$.For $n = 12$,$A_{12} = 7 + (12 - 1) 	imes 2 = 7 + 11 	imes 2 = 7 + 22 = 29$.Therefore,the $12^{th}$ term of the $H.P.$ is the reciprocal of $A_{12}$,which is $1/29$.

The first term of a harmonic progression is $1/7$ and the second term is $1/9$. The $12^{th}$ term is

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