The focus of the parabola ${x^2} = 2x + 2y$ is

  • A
    $\left( \frac{3}{2}, \frac{-1}{2} \right)$
  • B
    $\left( 1, \frac{-1}{2} \right)$
  • C
    $(1, 0)$
  • D
    $(0, 1)$

Explore More

Similar Questions

The point on the parabola $2y = x^2$ which is nearest to the point $(0, 3)$ is

Difficult
View Solution

Find the equation of the normal to the curve $x^{2}=4y$ which passes through the point $(1,2)$.

Difficult
View Solution

If one of the vertices of an equilateral triangle inscribed in the parabola $y^2=12x$ coincides with the vertex of the parabola, then the area (in sq. units) of that triangle is (in $\sqrt{3}$)

Find the point where the normal at the point $(4, 4)$ intersects the parabola $y^2 = 4x$ again.

Let the locus of the points from which the tangents drawn to $y = x^2$ make an angle of $45^{\circ}$ with each other be $16y^2 - 16x^2 + ky + 1 = 0$. Then $k$ is equal to:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo