The following are the ages of $300$ patients getting medical treatment in a hospital on a particular day:
Age (in years) $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$
Number of patients $60$ $42$ $55$ $70$ $53$ $20$

Form:
$(i)$ Less than type cumulative frequency distribution.
$(ii)$ More than type cumulative frequency distribution.

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(N/A) $(i)$ To form a 'less than' type cumulative frequency distribution,we add the frequencies of all classes preceding the current class. Since the data starts from $10-20$,we assume $0$ patients are less than $10$ years old.
$(ii)$ To form a 'more than' type cumulative frequency distribution,we start with the total number of patients $(300)$ and subtract the frequency of each preceding class interval.
Age (in years) Less than type (Cumulative Frequency) Age (in years) More than type (Cumulative Frequency)
Less than $10$ $0$ $10$ or more $300$
Less than $20$ $60$ $20$ or more $240$
Less than $30$ $102$ $30$ or more $198$
Less than $40$ $157$ $40$ or more $143$
Less than $50$ $227$ $50$ or more $73$
Less than $60$ $280$ $60$ or more $20$
Less than $70$ $300$ $70$ or more $0$

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Similar Questions

Class$0-10$$10-20$$20-30$$30-40$$40-50$
Frequency$10$$12$$13$$16$$9$

For the frequency distribution given above,which of the following is false?

For some given data,if $\bar{x} + Z = 37.5$ and $\bar{x} - Z = 1.5$,then $M = \ldots$

For some given data,if $M + \bar{x} = 165$ and $M - \bar{x} = 1$,then $Z = \dots$

If $Z+M=34$ and $M+\bar{x}=40,$ then $M=\ldots \ldots \ldots . . .$

The following data gives the distribution of total monthly household expenditure of $200$ families of a village. Find the modal monthly expenditure of the families. Also,find the mean monthly expenditure:
$\begin{array}{|c|c|} \hline \text{Expenditure (in Rs)} & \text{Number of families} \\ \hline 1000-1500 & 24 \\ 1500-2000 & 40 \\ 2000-2500 & 33 \\ 2500-3000 & 28 \\ 3000-3500 & 30 \\ 3500-4000 & 22 \\ 4000-4500 & 16 \\ 4500-5000 & 7 \\ \hline \end{array}$

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