(D) The rate law is given by $R = k[X]^x[Y]^y$.From experiment $1$ and $2$,keeping $[Y]$ constant:$\frac{R_2}{R_1} = \frac{k[0.50]^x[0.25]^y}{k[0.25]^

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(D) The rate law is given by $R = k[X]^x[Y]^y$.From experiment $1$ and $2$,keeping $[Y]$ constant:$\frac{R_2}{R_1} = \frac{k[0.50]^x[0.25]^y}{k[0.25]^x[0.25]^y} = \frac{4.0 \times 10^{-6}}{1.0 \times 10^{-6}}$$2^x = 4$ $\Rightarrow 2^x = 2^2$ $\Rightarrow x = 2$.From experiment $1$ and $3$,keeping $[X]$ constant:$\frac{R_3}{R_1} = \frac{k[0.25]^x[0.50]^y}{k[0.25]^x[0.25]^y} = \frac{8.0 \times 10^{-6}}{1.0 \times 10^{-6}}$$2^y = 8$ $\Rightarrow 2^y = 2^3$ $\Rightarrow y = 3$.The overall order of the reaction is $x + y = 2 + 3 = 5$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

The following data are obtained for a reaction,$X + Y \rightarrow$ Products.

$Expt.$ $[X]_0 / mol \ L^{-1}$ $[Y]_0 / mol \ L^{-1}$ $Rate / mol \ L^{-1} s^{-1}$

$1$ $0.25$ $0.25$ $1.0 \times 10^{-6}$

$2$ $0.50$ $0.25$ $4.0 \times 10^{-6}$

$3$ $0.25$ $0.50$ $8.0 \times 10^{-6}$

The overall order of the reaction is:

KVPY 2012 All KVPY

A
$2$
B
$4$
C
$3$
D
$5$

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Class 12

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Chemical Kinetics

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Rate law , Rate constant , Order of Reaction and Molecularity

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MediumNEET 2013

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Write the differential rate expression for the following reactions and determine their order of reaction:
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For a certain reaction,the expression for half-life is $t_{1/2} \propto \frac{1}{a^{n-1}}$. What is the order of the reaction?

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In a chemical reaction $A$ is converted into $B$. The rates of reaction,starting with initial concentrations of $A$ as $2 \times 10^{-3} \ M$ and $1 \times 10^{-3} \ M$,are equal to $2.40 \times 10^{-4} \ M s^{-1}$ and $0.60 \times 10^{-4} \ M s^{-1}$ respectively. The order of reaction with respect to reactant $A$ will be

DifficultAIEEE 2012

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$Expt.$	$[X]_0 / mol \ L^{-1}$	$[Y]_0 / mol \ L^{-1}$	$Rate / mol \ L^{-1} s^{-1}$
$1$	$0.25$	$0.25$	$1.0 \times 10^{-6}$
$2$	$0.50$	$0.25$	$4.0 \times 10^{-6}$
$3$	$0.25$	$0.50$	$8.0 \times 10^{-6}$

Similar Questions

Inversion of cane sugar is an example of $-$

For a reaction between $A$ and $B$,the order with respect to $A$ is $2$ and the order with respect to $B$ is $3$. If the concentrations of both $A$ and $B$ are doubled,the rate will increase by a factor of:

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Write the differential rate expression for the following reactions and determine their order of reaction:
$1) \ 2 \ HI \rightarrow H_2 + I_2$
$2) \ 2 \ NO_{(g)} + O_{2(g)} \rightarrow 2 \ NO_{2(g)}$