The following is the distribution of weights (in $kg$) of $40$ persons:
Weight (in $kg$) $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ $65-70$ $70-75$ $75-80$ Number of persons $4$ $4$ $13$ $5$ $6$ $5$ $2$ $1$
Construct a cumulative frequency distribution (of the less than type) table for the data above.
| Weight (in $kg$) | $40-45$ | $45-50$ | $50-55$ | $55-60$ | $60-65$ | $65-70$ | $70-75$ | $75-80$ |
| Number of persons | $4$ | $4$ | $13$ | $5$ | $6$ | $5$ | $2$ | $1$ |
Construct a cumulative frequency distribution (of the less than type) table for the data above.
(N/A) To construct a cumulative frequency distribution (less than type),we add the frequencies of all classes preceding the upper limit of the current class.
| Weight (in $kg$) | Cumulative Frequency |
| Less than $45$ | $4$ |
| Less than $50$ | $4 + 4 = 8$ |
| Less than $55$ | $8 + 13 = 21$ |
| Less than $60$ | $21 + 5 = 26$ |
| Less than $65$ | $26 + 6 = 32$ |
| Less than $70$ | $32 + 5 = 37$ |
| Less than $75$ | $37 + 2 = 39$ |
| Less than $80$ | $39 + 1 = 40$ |
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Similar Questions
The median of the following frequency distribution is $49$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $2$ $6$ $8$ $x$ $20$ $18$ $y$ $14$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $2$ | $6$ | $8$ | $x$ | $20$ | $18$ | $y$ | $14$ |
Medium
View SolutionFind the median of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $2$ $6$ $8$ $16$ $20$ $18$ $16$ $14$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $2$ | $6$ | $8$ | $16$ | $20$ | $18$ | $16$ | $14$ |
Difficult
View SolutionThe median of the following frequency distribution is $46$ and the total frequency is $230$. Find the missing frequencies $x$ and $y$.
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $12$ $30$ $x$ $65$ $y$ $25$ $18$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $12$ | $30$ | $x$ | $65$ | $y$ | $25$ | $18$ |
Difficult
View SolutionThe two types of Ogives drawn for a frequency distribution intersect at point $(20, 25)$. Then,the median of the data is .......
Easy
View SolutionThe percentage of marks obtained by $100$ students in an examination are given below:
Marks $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ Frequency $14$ $16$ $18$ $23$ $18$ $8$ $3$
Determine the median percentage of marks.
| Marks | $30-35$ | $35-40$ | $40-45$ | $45-50$ | $50-55$ | $55-60$ | $60-65$ |
| Frequency | $14$ | $16$ | $18$ | $23$ | $18$ | $8$ | $3$ |
Determine the median percentage of marks.
Medium
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