The following sets of values for {C_V} and {C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an ideal gas,the relationship between molar specific heats is given by Mayer's relation: ${C_P} - {C_V} = R$.Given the units are in $cal/gm-mo

Vedclass · Accepted Answer

${C_V} = 3, {C_P} = 5$

Vedclass · Answer

(A) For an ideal gas,the relationship between molar specific heats is given by Mayer's relation: ${C_P} - {C_V} = R$.Given the units are in $cal/gm-mole-K$,the universal gas constant $R \approx 2 \; cal/mol-K$.For a monoatomic gas,${C_V} = \frac{3}{2}R = 3 \; cal/mol-K$ and ${C_P} = \frac{5}{2}R = 5 \; cal/mol-K$.Checking the options:Option $A$: ${C_P} - {C_V} = 5 - 3 = 2 = R$. This satisfies Mayer's relation.Option $B$: ${C_P} - {C_V} = 6 - 4 = 2 = R$. While this satisfies Mayer's relation,${C_V} = 4$ is not a standard value for simple ideal gases.Option $C$: ${C_P} Option $D$: ${C_P} - {C_V} = 4.2 - 3 = 1.2 
eq R$.Thus,the set in option $A$ is the most reliable as it corresponds to the theoretical values for a monoatomic gas.

The following sets of values for ${C_V}$ and ${C_P}$ of a gas have been reported by different students. The units are $cal/gm-mole-K$. Which of these sets is most reliable?

Similar Questions

Select the incorrect statement about the specific heats of a gaseous system.

The value of $C_V$ for one mole of neon gas is

The ratio of specific heats $\left(\frac{C_{P}}{C_{V}}\right)$ in terms of degree of freedom $(f)$ is given by

When $40 \ J$ of heat is absorbed by a monatomic gas,the increase in the internal energy of the gas is (in $J$)

If the specific heats of a monoatomic gas and a diatomic gas are the same, which relation is valid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module