The formula to find the median of a grouped data is $\ldots \ldots \ldots \ldots .$

  • A
    $M = 3Z - 2\bar{x}$
  • B
    $M = l + \left( \frac{\frac{n}{2} - cf}{f} \right) \times h$
  • C
    $M = l + \left( \frac{\frac{n}{2} - cf}{f_1 - f_2} \right) \times h$
  • D
    $M = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h$

Explore More

Similar Questions

Find the unknown entries $a, b, c, d, e, f$ in the following distribution of heights of students in a class:
Height (in $cm$) Frequency Cumulative frequency
$150-155$ $12$ $a$
$155-160$ $b$ $25$
$160-165$ $10$ $c$
$165-170$ $d$ $43$
$170-175$ $e$ $48$
$175-180$ $2$ $f$
Total $50$ -

$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years)Number of policy holders
Below $20$$2$
Below $25$$6$
Below $30$$24$
Below $35$$45$
Below $40$$78$
Below $45$$89$
Below $50$$92$
Below $55$$98$
Below $60$$100$

Difficult
View Solution

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$n = \ldots \ldots \ldots$

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$

Find the median of the following frequency distribution:
Class Frequency $(f)$
$110-120$ $6$
$120-130$ $25$
$130-140$ $48$
$140-150$ $72$
$150-160$ $116$
$160-170$ $60$
$170-180$ $38$
$180-190$ $22$
$190-200$ $3$

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo