In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$
- Acumulative frequency of the class preceding the median class
- Bfrequency of the median class
- Cclass size (class length)
- Dlower limit of the median class
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Similar Questions
Consider the following frequency distribution:
Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$ Frequency $13$ $10$ $15$ $8$ $11$
The upper limit of the median class is
| Class | $0-5$ | $6-11$ | $12-17$ | $18-23$ | $24-29$ |
| Frequency | $13$ | $10$ | $15$ | $8$ | $11$ |
The upper limit of the median class is
Medium
View SolutionThe formula to find the median of a grouped data is $\ldots \ldots \ldots \ldots .$
Easy
View SolutionIn the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$f = \ldots \ldots \ldots$
Easy
View SolutionThe median of the following frequency distribution is $28.5$ and the total frequency is $60$. Find the missing frequencies $x$ and $y$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $5$ $x$ $20$ $15$ $y$ $5$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $5$ | $x$ | $20$ | $15$ | $y$ | $5$ |
Medium
View SolutionTo draw the 'less than' type Ogive,........... is represented on the $X$-axis.
Easy
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