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(A) To find the median class,we first convert the discontinuous class intervals into continuous ones by adjusting the boundaries. The difference betwe

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$17.5$

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(A) To find the median class,we first convert the discontinuous class intervals into continuous ones by adjusting the boundaries. The difference between the upper limit of one class and the lower limit of the next is $1$. Thus,we subtract $0.5$ from the lower limit and add $0.5$ to the upper limit.						Class			Frequency $(f)$			Cumulative Frequency $(cf)$							$-0.5-5.5$			$13$			$13$							$5.5-11.5$			$10$			$23$							$11.5-17.5$			$15$			$38$							$17.5-23.5$			$8$			$46$							$23.5-29.5$			$11$			$57$			The total frequency $N = 57$. The median position is $N/2 = 57/2 = 28.5$. The cumulative frequency just greater than $28.5$ is $38$,which corresponds to the class interval $11.5-17.5$. Therefore,the median class is $11.5-17.5$. The upper limit of this class is $17.5$.

Class (seconds)	$13.8-14.0$	$14.0-14.2$	$14.2-14.4$	$14.4-14.6$	$14.6-14.8$	$14.8-15.0$
Frequency	$2$	$4$	$5$	$71$	$48$	$20$

Class	$60-70$	$70-80$	$80-90$	$90-100$	$100-110$	$110-120$
Frequency	$5$	$15$	$20$	$30$	$20$	$8$

Consider the following frequency distribution:

Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$

Frequency $13$ $10$ $15$ $8$ $11$

The upper limit of the median class is

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Find the median of the following frequency distribution:

Class $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ $65-70$ $70-75$

Frequency $1$ $2$ $5$ $10$ $17$ $15$ $9$ $5$ $3$

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The times,in seconds,taken by $150$ athletes to run a $110\, m$ hurdle race are tabulated below:

Class (seconds) $13.8-14.0$ $14.0-14.2$ $14.2-14.4$ $14.4-14.6$ $14.6-14.8$ $14.8-15.0$

Frequency $2$ $4$ $5$ $71$ $48$ $20$

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Find the median of the following frequency distribution:

Class $60-70$ $70-80$ $80-90$ $90-100$ $100-110$ $110-120$

Frequency $5$ $15$ $20$ $30$ $20$ $8$

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Class	$0-5$	$6-11$	$12-17$	$18-23$	$24-29$
Frequency	$13$	$10$	$15$	$8$	$11$

Consider the following frequency distribution: Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$ Frequency $13$ $10$ $15$ $8$ $11$ The upper limit of the median class is