The fringe width in an interference pattern is $X$. The distance between the sixth dark fringe from one side of the central bright band to the fourth bright fringe on the other side is: (in $X$)

In Young's double slit experiment,the amplitudes of the two waves incident on the two slits are $A$ and $2A$. If $I_{0}$ is the maximum intensity,then the intensity at a spot on the screen,where the phase difference between the two interfering waves is $\phi$,is:

Explain Young's double-slit experiment,its experimental arrangement,and how it produces an interference pattern.

In a double slit experiment with monochromatic light,fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by $5 \times 10^{-2} \,m$ towards the slits,the change in fringe width is $3 \times 10^{-3} \,cm$. If the distance between the slits is $1 \,mm$,then the wavelength of the light will be . . . . . . $nm$.

Young's double slit experiment is performed with light of wavelength $550 \, nm$. The separation between the slits is $1.10 \, mm$ and the screen is placed at a distance of $1 \, m$. What is the distance between consecutive bright or dark fringes in $mm$?

The fringe width for red colour as compared to that for violet colour is approximately (in $\times$)