The geometry and the number of unpaired elect | vedclass

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(C) The oxidation state of $Mn$ in $[MnBr_4]^{2-}$ is $+2$.The electronic configuration of $Mn^{2+}$ is $[Ar] 3d^{5} 4s^{0}$.Since $Br^{-}$ is a weak

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tetrahedral and $5$

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(C) The oxidation state of $Mn$ in $[MnBr_4]^{2-}$ is $+2$.The electronic configuration of $Mn^{2+}$ is $[Ar] 3d^{5} 4s^{0}$.Since $Br^{-}$ is a weak field ligand,pairing of electrons will not occur.As the hybridisation of $Mn$ in $[MnBr_4]^{2-}$ is $sp^{3}$,its geometry is tetrahedral and it contains $5$ unpaired electrons.$Mn^{2+}$ (Ground state): $3d$ $(1|1|1|1|1)$ $4s$ ( ) $4p$ ( ) ( )$[MnBr_4]^{2-}$: $3d$ $(1|1|1|1|1)$ $4s$ ( ) $4p$ ( ) ( ) ( ) $\rightarrow sp^{3}$ hybridisation

The geometry and the number of unpaired electron$(s)$ of $[MnBr_4]^{2-}$,respectively,are

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