The geometries of Ni(CO)_4 and Ni(PPh_3)_2Cl_ | vedclass

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(D) In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The configuration is $[Ar] 3d^8 4s^2$. Due to the strong field ligand $CO$,the electrons pair up

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Both tetrahedral

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(D) In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The configuration is $[Ar] 3d^8 4s^2$. Due to the strong field ligand $CO$,the electrons pair up,resulting in $sp^3$ hybridization,which gives a tetrahedral geometry.In $Ni(PPh_3)_2Cl_2$,the oxidation state of $Ni$ is $+2$. The configuration is $[Ar] 3d^8$. $PPh_3$ is a bulky ligand,and $Cl^-$ is a weak field ligand. The steric hindrance caused by $PPh_3$ groups forces the complex to adopt a tetrahedral geometry ($sp^3$ hybridization) rather than square planar.

The geometries of $Ni(CO)_4$ and $Ni(PPh_3)_2Cl_2$ are:

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