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(D) The chemical formula for Cuproammonium sulphate is $[Cu(NH_{3})_{4}]SO_{4} \cdot H_{2}O$.In the complex ion $[Cu(NH_{3})_{4}]^{2+}$,the oxidation

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Paramagnetic and square planar

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(D) The chemical formula for Cuproammonium sulphate is $[Cu(NH_{3})_{4}]SO_{4} \cdot H_{2}O$.In the complex ion $[Cu(NH_{3})_{4}]^{2+}$,the oxidation state of $Cu$ is $+2$.The electronic configuration of $Cu^{2+}$ is $[Ar] 3d^{9}$.Due to the presence of $NH_{3}$ (a strong field ligand),the complex undergoes $dsp^{2}$ hybridization,resulting in a square planar geometry.Since there is one unpaired electron in the $3d$ orbital,the complex is paramagnetic.

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

What is the type of magnetic behavior and geometry respectively in Cuproammonium sulphate (Atomic no. of $Cu=29$)?

Similar Questions

In solid $CuSO_4 \cdot 5H_2O$,copper is coordinated to:

Match the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$ $(ii). [Ni(CO)_4]$
$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$ $(iv). [CoF_6]^{3-}$
$(v). [Fe(CO)_5]$

What is the number of unpaired electrons in $[Co(NH_3)_6]^{3+}$ complex?

Which set of $d-$ orbitals is used by the central metal during the formation of $MnO_4^-$?

Which of the following complexes exhibits $sp^{3}d$ hybridization?

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