What is the number of unpaired electrons in $[Co(NH_3)_6]^{3+}$ complex?
- A$4$
- B$3$
- C$2$
- DZero
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Similar Questions
Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is
$LIST-I$ $LIST-II$ $P. dsp^2$ $1. [FeF_6]^{4-}$ $Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$ $R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$ $S. d^2sp^3$ $4. [FeCl_4]^{2-}$ $5. Ni(CO)_4$ $6. [Ni(CN)_4]^{2-}$
| $LIST-I$ | $LIST-II$ |
| $P. dsp^2$ | $1. [FeF_6]^{4-}$ |
| $Q. sp^3$ | $2. [Ti(H_2O)_3Cl_3]$ |
| $R. sp^3d^2$ | $3. [Cr(NH_3)_6]^{3+}$ |
| $S. d^2sp^3$ | $4. [FeCl_4]^{2-}$ |
| $5. Ni(CO)_4$ | |
| $6. [Ni(CN)_4]^{2-}$ |
MediumIIT 2018
View SolutionMatch List-$I$ (Species) with List-$II$ (Hybrid orbitals used by the central atom in their formation) and select the correct answer.
List-$I$ List-$II$ $A. \, Ni(CN)_5^{3-}$ $1. \, sp^3$ $B. \, CuCl_5^{3-}$ $2. \, dsp^2$ $C. \, AuCl_4^-$ $3. \, sp^3d_{z^2}$ $D. \, ClO_4^-$ $4. \, d_{x^2-y^2}sp^3$
| List-$I$ | List-$II$ |
| $A. \, Ni(CN)_5^{3-}$ | $1. \, sp^3$ |
| $B. \, CuCl_5^{3-}$ | $2. \, dsp^2$ |
| $C. \, AuCl_4^-$ | $3. \, sp^3d_{z^2}$ |
| $D. \, ClO_4^-$ | $4. \, d_{x^2-y^2}sp^3$ |
Difficult
View Solution$[Cu(NH_3)_4]^{2+}$ shows the following hybridization:
Which one of the following complexes is an outer orbital complex?
Medium
View SolutionWhat type of hybridization is found in $[Ni(Cl)_4]^{2-}$?
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