What type of hybridization is found in [Ni(Cl | vedclass

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(A) $1$. The central metal ion is $Ni^{2+}$. The atomic number of $Ni$ is $28$, so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$2$. $Cl^-

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$sp^3$

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(A) $1$. The central metal ion is $Ni^{2+}$. The atomic number of $Ni$ is $28$, so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$2$. $Cl^-$ is a weak field ligand, so it does not cause pairing of electrons in the $3d$ orbitals.$3$. The $3d$ orbitals remain as $3d^8$ with two unpaired electrons.$4$. To accommodate four $Cl^-$ ligands, the metal ion uses one $4s$ and three $4p$ orbitals.$5$. Thus, the hybridization is $sp^3$, resulting in a tetrahedral geometry.

What type of hybridization is found in $[Ni(Cl)_4]^{2-}$?

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