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(C) In the given circuit,the branch $BD$ contains an $8 	ext{ V}$ battery. For a Wheatstone bridge to be balanced,there should be no potential differ

Vedclass · Accepted Answer

$V_B - V_D = 8 	ext{ V}$

Vedclass · Answer

(C) In the given circuit,the branch $BD$ contains an $8 	ext{ V}$ battery. For a Wheatstone bridge to be balanced,there should be no potential difference across the central branch,or the ratio of resistances in the arms must be equal. Here,the resistances are $R_{AB} = 4 \ \Omega$,$R_{BC} = 4 \ \Omega$,$R_{AD} = 4 \ \Omega$,and $R_{DC} = 4 \ \Omega$. Since $R_{AB}/R_{AD} = R_{BC}/R_{DC} = 4/4 = 1$,the bridge is balanced in terms of resistance ratios. However,there is an $8 	ext{ V}$ battery connected between points $B$ and $D$. Therefore,the potential difference between $B$ and $D$ is fixed by the battery,i.e.,$V_B - V_D = 8 	ext{ V}$. Since $V_B - V_D 
eq 0$,current will flow through the branch $BD$ due to the $8 	ext{ V}$ battery. Thus,the correct statement is $V_B - V_D = 8 	ext{ V}$.

The given figure shows a network of resistances and a battery. Identify the correct statement$(s)$.

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