The graph between log R and log A,where R is | vedclass

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(A) The relationship between the nuclear radius $R$ and the mass number $A$ is given by the formula:$R = R_0 A^{1/3}$where $R_0$ is a constant $(R_0 \

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(A) The relationship between the nuclear radius $R$ and the mass number $A$ is given by the formula:$R = R_0 A^{1/3}$where $R_0$ is a constant $(R_0 \approx 1.2 	imes 10^{-15} 	ext{ m})$.Taking the natural logarithm on both sides:$\ln R = \ln(R_0 A^{1/3})$$\ln R = \ln R_0 + \ln(A^{1/3})$$\ln R = \ln R_0 + \frac{1}{3} \ln A$This equation is of the form $y = mx + c$,where $y = \ln R$,$x = \ln A$,the slope $m = 1/3$,and the intercept $c = \ln R_0$.Since the slope is positive $(1/3)$,the graph of $\log R$ versus $\log A$ is a straight line with a positive slope.

The graph between $\log R$ and $\log A$,where $R$ is the nuclear radius and $A$ is the mass number,is:

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