(C) According to Einstein's photoelectric equation,the stopping potential $V_{s}$ is given by: $eV_{s} = h\nu - \phi$ $V_{s} = \frac{h}{e}\nu - \frac{

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(C) According to Einstein's photoelectric equation,the stopping potential $V_{s}$ is given by: $eV_{s} = h\nu - \phi$ $V_{s} = \frac{h}{e}\nu - \frac{\phi}{e}$ Comparing this with the equation of a straight line $y = mx + c$,the x-intercept (where $V_{s} = 0$) is the threshold frequency $\nu_{0}$,where $\nu_{0} = \frac{\phi}{h}$ or $\phi = h\nu_{0}$. From the given graph,the threshold frequency for metal '$P$' is $\nu_{0}$ and for metal '$Q$' is $\nu_{0}^{\prime}$. Since $\nu_{0} Therefore,the work function $\phi_{P} < \phi_{Q}$.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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The graph of stopping potential $(V_{s})$ against frequency $(\nu)$ of incident radiation is plotted for two different metals '$P$' and '$Q$' as shown in the graph. If $\phi_{P}$ and $\phi_{Q}$ are the work functions of metals '$P$' and '$Q$' respectively,then which of the following is correct?

MHT CET 2020 All MHT CET

A
$\phi_{P} = \phi_{Q}$
B
$\nu_{0} < \nu_{0}^{\prime}$
C
$\phi_{P} < \phi_{Q}$
D
$\phi_{P} > \phi_{Q}$

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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DifficultJEE MAIN 2026

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The graph of stopping potential $(V_{s})$ against frequency $(\nu)$ of incident radiation is plotted for two different metals '$P$' and '$Q$' as shown in the graph. If $\phi_{P}$ and $\phi_{Q}$ are the work functions of metals '$P$' and '$Q$' respectively,then which of the following is correct?

Similar Questions

When radiation is incident on a photoelectron emitter,the stopping potential is found to be $9 \ V$. If $e/m$ for the electron is $1.8 \times 10^{11} \ C \ kg^{-1}$,the maximum velocity of the ejected electrons is:

When a photon of energy $6 \ eV$ is incident on a metal surface with a work function of $2.1 \ eV$,what is the stopping potential of the emitted electrons in $V$?

If the surface of a metal is successively exposed to radiation of wavelengths $\lambda_1 = 350 \, nm$ and $\lambda_2 = 450 \, nm$,the maximum velocity of photoelectrons differs by a factor of $2$. The work function of this metal is:

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