The highest boiling point is expected for

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(C) Among alkanes,the boiling point increases with an increase in molecular weight. For isomeric alkanes,straight-chain alkanes have a higher boiling

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$n-$octane

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(C) Among alkanes,the boiling point increases with an increase in molecular weight. For isomeric alkanes,straight-chain alkanes have a higher boiling point than branched alkanes because they have a larger surface area,leading to stronger van der Waals forces. Comparing the given options: $(A)$ $n-$butane $(C_4H_{10})$ has the lowest molecular weight. $(B)$,$(C)$,and $(D)$ are isomers with the molecular formula $C_8H_{18}$. Among these,$n-$octane is a straight-chain alkane,while iso-octane and $2, 2, 3, 3-$tetramethyl butane are branched. Therefore,$n-$octane has the highest boiling point.

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