The increasing order of basicity for the following intermediates is (from weak to strong):
$(i)$ $(CH_3)_3C^{-}$
$(ii)$ $H_2C=CH-CH_2^{-}$
$(iii)$ $HC \equiv C^{-}$
$(iv)$ $CH_3^{-}$
$(v)$ $CN^{-}$

  • A
    $(v) < (i) < (iv) < (ii) < (iii)$
  • B
    $(iii) < (i) < (ii) < (iv) < (v)$
  • C
    $(v) < (iii) < (ii) < (iv) < (i)$
  • D
    $(iii) < (iv) < (ii) < (i) < (v)$

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Similar Questions

The hybridization of the positively charged carbon and the negatively charged carbon in the following structures are respectively:

Which of the following are secondary radicals?
$(1) \ CH_3 - \dot{C}H - C_2H_5$
$(2) \ CH_2 = \dot{C} - CH_3$
$(3) \ CH_2 = CH - \dot{C}H_2$
$(4) \ (CH_3)_2 \dot{C}H$

In which pairs,the first ion is more stable than the second?

Arrange the following carbocations in decreasing order of their stability:
$\stackrel{+}{C}H_3, (CH_3)_3\stackrel{+}{C}, CH_3\stackrel{+}{C}H_2, (CH_3)_2\stackrel{+}{C}H$

The correct order of stability of the following carbocations is:

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