The increasing order of boiling points of the | vedclass

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,

Vedclass · Accepted Answer

$III < I < II < IV$

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,which only has weak London dispersion forces. It has the lowest boiling point.$2$. $CH_3-O-CH_3$ $(I)$: This is an ether,which has weak dipole-dipole interactions. Its boiling point is higher than the alkane but lower than polar molecules with stronger interactions.$3$. $CH_3CHO$ $(II)$: This is an aldehyde,which has stronger dipole-dipole interactions due to the polar $C=O$ bond.$4$. $CH_3CH_2OH$ $(IV)$: This is an alcohol,which exhibits strong intermolecular hydrogen bonding. It has the highest boiling point among these.Thus,the increasing order of boiling points is $III < I < II < IV$.

Molecule	Label
$CH_3-O-CH_3$	$I$
$CH_3CHO$	$II$
$CH_3CH_2CH_3$	$III$
$CH_3CH_2OH$	$IV$

Column-$I$	Column-$II$
$(i)$ $2-$methylphenol	$(a)$ Hydroquinone
$(ii)$ Benzene$-1,2-$diol	$(b)$ Phenetole
$(iii)$ Benzene$-1,3-$diol	$(c)$ Catechol
$(iv)$ Benzene$-1,4-$diol	$(d)$ $o$-Cresol
$(v)$ Methoxybenzene	$(e)$ Quinone
$(vi)$ Ethoxybenzene	$(f)$ Resorcinol
	$(g)$ Anisole

Column-$I$: Compound / Reagent	Column-$II$: Other name / Chemical / Process
$A$. Methanol	$I$. Lucas reagent
$B$. $ZnCl_2$ / Conc. $HCl$	$II$. Baeyer's reagent
$C$. Rectified spirit	$III$. Wood spirit
$D$. Dil. $KMnO_4$	$IV$. $95 \% C_2H_5OH$
-	$V$. $75 \% C_2H_5OH$
-	$VI$. $90 \% C_3H_7OH$

The increasing order of boiling points of the following is:
Molecule Label
$CH_3-O-CH_3$ $I$
$CH_3CHO$ $II$
$CH_3CH_2CH_3$ $III$
$CH_3CH_2OH$ $IV$

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The increasing order of boiling points of the following is:MoleculeLabel$CH_3-O-CH_3$$I$$CH_3CHO$$II$$CH_3CH_2CH_3$$III$$CH_3CH_2OH$$IV$