The inner diameter of a cylindrical wooden pi | vedclass

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(D) Given:Inner diameter $= 24 \, cm$,so inner radius $(r) = 12 \, cm$.Outer diameter $= 28 \, cm$,so outer radius $(R) = 14 \, cm$.Length of the pipe

Vedclass · Accepted Answer

$3.432$

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(D) Given:Inner diameter $= 24 \, cm$,so inner radius $(r) = 12 \, cm$.Outer diameter $= 28 \, cm$,so outer radius $(R) = 14 \, cm$.Length of the pipe $(h) = 35 \, cm$.The volume of wood in the pipe is the difference between the outer volume and the inner volume:$V = \pi R^2 h - \pi r^2 h = \pi h (R^2 - r^2) = \pi h (R + r)(R - r)$.Substituting the values:$V = \frac{22}{7} 	imes 35 	imes (14 + 12) 	imes (14 - 12) \, cm^3$.$V = 22 	imes 5 	imes 26 	imes 2 = 5720 \, cm^3$.Mass of the wood $= 	ext{Volume} 	imes 	ext{Density} = 5720 \, cm^3 	imes 0.6 \, g/cm^3$.Mass $= 3432 \, g$.Converting to kilograms: $3432 \, g = 3.432 \, kg$.

The inner diameter of a cylindrical wooden pipe is $24 \, cm$ and its outer diameter is $28 \, cm$. The length of the pipe is $35 \, cm$. Find the mass of the pipe,if $1 \, cm^3$ of wood has a mass of $0.6 \, g$. (in $, kg$)

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