The isoelectronic set of ions is

  • A
    $Li^{+}, Na^{+}, O^{2-}$ and $F^{-}$
  • B
    $F^{-}, Li^{+}, Na^{+}$ and $Mg^{2+}$
  • C
    $N^{3-}, O^{2-}, F^{-}$ and $Na^{+}$
  • D
    $N^{3-}, Li^{+}, Mg^{2+}$ and $O^{2-}$

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$C.$ The $1^{st}$ ionization energy of boron is less than that of beryllium.
$D.$ The electronegativity of $C$ is $2.5$ in $CH_4$ and $CCl_4$.
$E.$ $Li$ is the most electropositive among elements of group $I$.
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In which of the following arrangements,the sequence does not strictly follow the property indicated against it?

An element $E$ has an ionisation enthalpy value of $374 \ kJ \ mol^{-1}$. $E$ reacts with elements $A, B, C$ and $D$ with electron gain enthalpy values of $-328, -349, -325$ and $-295 \ kJ \ mol^{-1}$,respectively. The correct order of the products $EA, EB, EC$ and $ED$ in terms of ionic character is $:$

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Outermost electronic configuration of a group $13$ element,$E$,is $4s^2 4p^1$. The electronic configuration of an element of $p$-block,period $5$,placed diagonally to element $E$ is:

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