The last digit of $2^5 \cdot 5^5$ is........

Express $96$ as a product of prime factors.

Show that any positive odd integer is of the form $6q+1$,$6q+3$,or $6q+5$,where $q$ is some integer.

$A$ positive integer is of the form $3q + 1$,where $q$ is a natural number. Can you write its square in any form other than $3m + 1$,i.e.,$3m$ or $3m + 2$ for some integer $m$? Justify your answer.

For any positive integer $n$,the last digit of $5^n$ is always.......

Show that every positive even integer is of the form $2q$,and that every positive odd integer is of the form $2q+1$,where $q$ is some integer.