The last orbit of argon would have how many electrons?

The atomic number of an element is $17$. The number of orbitals containing electron pairs in its valence shell is

Given below are the quantum numbers for $4$ electrons.
$A. \; n = 3, l = 2, m_l = 1, m_s = +1/2$
$B. \; n = 4, l = 1, m_l = 0, m_s = +1/2$
$C. \; n = 4, l = 2, m_l = -2, m_s = -1/2$
$D. \; n = 3, l = 1, m_l = -1, m_s = +1/2$
The correct order of increasing energy is

The electronic configuration $1s^{2}\, 2s^{2}\, 2p^{5}\, 3s^{1}$ represents:

The number of waves made by an electron moving in an orbit having a maximum magnetic quantum number $(m_l) = 3$ is:

Correct set of four quantum numbers for the outermost electron of rubidium $(Z=37)$ is :