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Question

(B) The maximum value of the magnetic quantum number $(m_l)$ is given as $3$. For a given subshell,the magnetic quantum number ranges from $-l$ to $+l

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The maximum value of the magnetic quantum number $(m_l)$ is given as $3$. For a given subshell,the magnetic quantum number ranges from $-l$ to $+l$. Thus,$l = 3$,which corresponds to an $f$-orbital. The principal quantum number $(n)$ is related to the orbital angular momentum quantum number $(l)$ by the relation $n = l + 1$ for the first occurrence of that subshell. Therefore,$n = 3 + 1 = 4$. According to the Bohr-Sommerfeld theory,the number of waves made by an electron in an orbit is equal to the principal quantum number $(n)$. Hence,the number of waves is $4$.

The number of waves made by an electron moving in an orbit having a maximum magnetic quantum number $(m_l) = 3$ is:

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